# C Program to Check if a Binary Tree is a Balanced Tree or not

A binary tree will be balanced tree if its both left subtree and right subtree is balanced i.e The difference between the height of left subtree and right subtree should not be more than 1. C program to check if a given binary tree is balanced or not is given below.

Ex: 1
A
/    \
C        D
\
E

This tree is a balanced tree, because the  height difference between  left subtree and right subtree of 'A'  is not more than one.

The height difference between left subtree and right subtree of C is not more than 1 and same with the subtrees of D as well as E.

Ex: 2

A
/     \
B        C
/
D
/
E

the above tree is not a balanced tree because height difference between left subtree and right subtree of C is more than 1.

PROGRAM:

```#include <stdio.h>
#include <stdlib.h>
struct node{
int data;
struct node *left;
struct node *right;
};
bool isBalanced(struct node *root);
int findheight(struct node *root)
{
int lefth=0,righth=0;
if(root==NULL)
{
return 0;
}
lefth=findheight(root->left);
righth=findheight(root->right);
if(lefth>righth)
{
return lefth+1;
}
else
{
return righth+1;
}
}
bool isBalanced(struct node *root)
{
int left_height,right_height;
if(root==NULL)
{
return true;
}
left_height=findheight(root->left);
right_height=findheight(root->right);
if(abs(left_height-right_height)<=1 && isBalanced(root->left) && isBalanced(root->right))
{
return true;
}
return false;
}
int main()
{

/*  Generating a binary tree

5
/   \
/     \
8       34
/ \
/   \
10     15
*/

struct node *root;
root=(struct node*)malloc(sizeof(struct node));
root->data=5;
root->left=(struct node*)malloc(sizeof(struct node));
root->left->data=8;
root->left->left=(struct node*)malloc(sizeof(struct node));
root->left->left->data=10;
root->left->left->left=root->left->left->right=NULL;
root->left->right=(struct node*)malloc(sizeof(struct node));
root->left->right->data=15;
root->left->right->left=root->left->right->right=NULL;

root->right=(struct node*)malloc(sizeof(struct node));
root->right->data=34;
root->right->left=root->right->right=NULL;

if(isBalanced(root))
{
printf("\n\n\nThe above given tree is a Balanced Tree\n\n\n");
}
else
{
printf("\n\n\nThe above given tree is not a Balanced Tree\n\n\n");
}
return 0;
}```

OUTPUT: