# Program to rotate an array to the left by N elements

This program will rotate an array to the left by n elements. C++ program along with output is given below.

Example:

Let A[] ={  3, 5, 6, 12, 89 }
r = 3   #rotate the array by r elements
Then output will be :    { 6, 12, 89, 3, 5 }

Algorithm:

For i in range(0,r):
temp=arr[0]
for j in range(0,n-1):
arr[j]=arr[j+1]
EndFor
arr[j]=temp
EndFor

PROGRAM:

```#include <stdio.h>
#define MAX 100000
void rotate(int arr[],int n);
int main()
{
int n,array[MAX],r;

printf("\nEnter the number of elements in array: ");
scanf("%d",&n);
printf("\nEnter the elements of the array: \n");
for(int j=0;j<n;j++)
{
scanf("%d",&array[j]);
}

printf("\nEnter the number of elements by which you want to rotate array: ");
scanf("%d",&r);
for(int j=1;j<=r;j++)
{
rotate(array,n);
}

printf("\n\nArray after rotation: \n");
for(int j=0;j<n;j++)
{
printf("%d ",array[j]);
}
return 0;
}
void rotate(int arr[],int n)
{
int temp=arr[0];
int i;
for(i=0;i<n-1;i++)
{
arr[i]=arr[i+1];
}
arr[i]=temp;
}```

OUTPUT: